Did a quick search and couldn't find this information anywhere online, so here goes.
Here's my scenario.
I Create new MVC project. (I'm using v4, but it would apply in earlier as well), and choose Internet Application. AccountModels.cs is created in my models folder.
There are 2 classes I'm concerned about. UserProfile and RegisterModel.
My scenario involves saving reuse and creating a partialview for creating and editing the user information. A fairly common scenario in web development.
So I create the partialview, and use the Model Declaration of UserProfile. I include all information inside of this that will be reused among the 2 views. In my situation, the password and confirm password are the fields I'm not re-using, so those won't be included in my partialview.
So my views look like:
_UserInfo (Partial View):
@model UserProfile
@Html.LabelFor(m => m.UserName)
@Html.TextBoxFor(m => m.UserName)
RegisterPage:
...
@Html.Partial("_UserInfo", Model)
@Html.LabelFor(m => m.Password)
@Html.PasswordFor(m => m.Password)
...
But wait! This generates an error msg stating that the model type is not the same. How do I pass a valid model type in so that my controller can still read the data back?
At the top of the RegistePage, I add the following:
@model RegisterModel
@{
ViewBag.Title = "Register";
UserProfile user = new UserProfile();
}
and change my RegisterPage to pass in user instead of Model, such as:
@Html.Partial("_UserInfo", user)
That's it! Now I can reuse this in an edit profile page and simply use UserProfile as my model type, and pass it into the partialview like:
@Html.Partial("_UserInfo", Model)
and the partialview will render it with no problems.
